20y^2+19y+3=

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Solution for 20y^2+19y+3= equation:


Simplifying
20y2 + 19y + 3 = 0

Reorder the terms:
3 + 19y + 20y2 = 0

Solving
3 + 19y + 20y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(3 + 4y)(1 + 5y) = 0

Subproblem 1

Set the factor '(3 + 4y)' equal to zero and attempt to solve: Simplifying 3 + 4y = 0 Solving 3 + 4y = 0 Move all terms containing y to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + 4y = 0 + -3 Combine like terms: 3 + -3 = 0 0 + 4y = 0 + -3 4y = 0 + -3 Combine like terms: 0 + -3 = -3 4y = -3 Divide each side by '4'. y = -0.75 Simplifying y = -0.75

Subproblem 2

Set the factor '(1 + 5y)' equal to zero and attempt to solve: Simplifying 1 + 5y = 0 Solving 1 + 5y = 0 Move all terms containing y to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + 5y = 0 + -1 Combine like terms: 1 + -1 = 0 0 + 5y = 0 + -1 5y = 0 + -1 Combine like terms: 0 + -1 = -1 5y = -1 Divide each side by '5'. y = -0.2 Simplifying y = -0.2

Solution

y = {-0.75, -0.2}

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